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Problem of the month (matrices, determinants):

Let A be an n-by-n matrix with integer entries such that each column is a permutation of the first column of A.
Prove that the sum of the entries of this column divides the determinant of A. For instance, if A is the matrix

6 5 9
5 9 5
9 6 6

then, one checks that det(A) = -240 which is divisible by 6 + 5 + 9 = 20.





More Problems of the Month

Problem Proposals:

American Mathematical Monthly

[*] A Toepletz Determinant | pdf
[*] Product of lcm's is a gcd | pdf
[11321] Characteristic polynomials of rational symmetric matrices | pdf
[11288] A polynomial product identity| pdf
[11231] A problem involving word equations in groups | pdf
[11204] A trace formula for sums of products of matrices | pdf
[11123] Snapshots of points moving on a line | pdf
[11098] Asymptotic behavior of a certain combinatorial sum | pdf
[10928] Powers sums of a convergent sum | pdf | ps
[10723] A sum congruence modulo a prime| pdf | ps

Mathematics Magazine

[1775] Graphs with a path connectivity property| pdf
[1750] Arithmetical progressions modulo a prime | pdf
[1684] Counting certain equivalence classes of words | pdf | ps

(* denotes to appear in an issue)

Selected Solutions:

[11226] pdf
[11085] pdf
[10851] pdf | ps
[10873] pdf | ps
[11028] pdf | ps
[11077] pdf | ps
[11096] pdf
[Put05] pdf

 












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