1 -3 2 0 1 5 4 10 1 1 3 band row reduce it, at least as far as is necessary. The row operations are
R2 -> R2-R1 R2 -> R2/8 R3 -> R3-4*R2 R3 -> R3-R1The matrix that results is
1 -3 2 0 0 1 1/4 5/4 0 0 0 b-5Hence, except for b=5, no solution exists.
Part (a).
Bê1= Bê2= 1 0 2 6 5 0 2 7Part (b). Bêj is the jth column of B.
AB= 3 2 6 -1 -4 -2
AB= 1 4 BA= 1 4 [A,B]= 0 0 4 -11 4 -11 0 0