{VERSION 2 3 "SUN SPARC SOLARIS" "2.3" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 }{PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }} {SECT 0 {EXCHG {PARA 0 "" 0 "" {TEXT -1 68 "I'll try to bring all unre turned old quizzes and exams to class Wed." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 74 "We will use the Maple m anual more now than before, particularly Chapter 7." }}{PARA 0 "" 0 " " {TEXT -1 33 "Exercises: p. 750 7, 11, 15, 17" }}{PARA 0 "" 0 "" {TEXT -1 25 "p. 762 1, 11, 15, 17, 19" }}{PARA 0 "" 0 "" {TEXT -1 0 " " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 13 "with(linalg);" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 28 "A:=matrix([[0, 1],[-2,-2]]); " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 7 "det(A);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 16 "eigenvectors(A);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "with(DEtools);" }}}{EXCHG {PARA 0 "" 0 " " {TEXT -1 28 "Example 9 in the Maple book." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 47 "de1:=diff(x(t),t)=-y(t)+(1-x(t)^2-y(t)^2)*x(t);" } }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 46 "de2:=diff(y(t),t)=x(t)+(1- x(t)^2-y(t)^2)*y(t);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 47 "ini ts:=\{[0,.5,0], [0,1.5,0], [0,2,0], [2,0,0]\};" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 22 "show:=x=-2..2,y=-2..2;" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 75 "DEplot([de1,de2],[x(t),y(t)],t=0..9,show,inits , stepsize=0.1, arrows=thin);" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 9 "1 2.3, 17." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "de1:=diff(x(t), t)=y(t);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 48 "de2:=diff(y(t), t)=-x(t)+epsilon*(1-x(t)^2)*y(t);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 55 "inits:= \{[0,1,0],[0,.5,0], [0,1.5,0], [0,2,0], [2,0,0]\};" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 35 "show:=x=-2..2,y=-2..2; epsilon:=.3;" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 75 "DEplot([de1,de2],[x(t),y(t)] ,t=0..6,show,inits, stepsize=0.1, arrows=thin);" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 9 "12.3, 11." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 64 "d1:=diff(x(t),t)=x(t)+y(t); d2:=diff(y(t),t)=5*y(t)-x(t)*y(t)+6;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 33 "solve(\{a+b=0,5*b-a*b+6=0 \},\{a,b\});" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 88 "inits:=\{[x (0)=3.5,y(0)=-3], [x(0)=2.5,y(0)=-2], [x(0)=1.5,y(0)=-2], [x(0)=2.5,y( 0)=-3]\};" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 84 "DEplot([d1,d2] ,[x(t),y(t)],t=0..6,x=1..4,y=-4..-1,inits, stepsize=0.1, arrows=thin); " }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 8 "12.3, 1." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 81 "d1:=diff(x(t),t)=3*x(t)+2*y(t)-y(t)^2; d2:=di ff(y(t),t)=-2*x(t)-2*y(t)+x(t)*y(t);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 55 "solve(\{3*a+2*b-b^2=0, -2*a-2*b+a*b=0\},\{a,b\}); eva lf(\");" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 86 "inits:=\{[x(0)=. 1,y(0)=0], [x(0)=.2,y(0)=-.2], [x(0)=.3,y(0)=-.4], [x(0)=.4,y(0)=-.5] \};" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 84 "DEplot([d1,d2],[x(t) ,y(t)],t=0..6,x=-1..1,y=-1..1,inits, stepsize=0.1, arrows=thin);" }} {PARA 0 "" 0 "" {TEXT -1 19 "Solutions to exam3." }}{PARA 0 "" 0 "" {TEXT -1 115 "1. Electrical circuit. i(t) is current through the 10 \+ ohm res, i1 through the inductor, i2 through the 5 ohm res." }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 144 "sys:=\{i(t)=i1(t)+i2(t), i1 (0)=0, i2(0)=0, i(0)=0, q(0)=0, 10*i(t)+20*diff(i1(t),t)=10, -20*diff( i1(t),t)+5*i2(t)+30*q(t)=0, i2(t)=diff(q(t),t)\};" }}}{EXCHG {PARA 0 " > " 0 "" {MPLTEXT 1 0 50 "sol1:=dsolve(sys,\{i(t),i1(t),i2(t),q(t)\},l aplace);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 16 "30*rhs(sol1[2]) ;" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 13 "1. mechanical" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 133 "restart; ms:=\{diff(x(t),t,t)=-x(t )+diff(y(t)-x(t),t), x(0)=-2, D(x)(0)=0, diff(y(t),t,t)=-y(t)+diff(x(t )-y(t),t), y(0)=0, D(y)(0)=0\};" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "dsolve(ms,\{x(t),y(t)\});" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 16 "with(inttrans): " }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 2 "2," }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 30 "invlaplace(exp(-3* s)/s^2,s,t);" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 2 "3." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 30 "alias(Y(s)=laplace(y(t),t,s));" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 51 "laplace(y(t)+int(y(v)*cos(2* (t-v)), v=0..t)=t,t,s);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 " solve(\",Y(s));" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 18 "invlapla ce(\",s,t);" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 2 "4." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 78 "dsolve(\{diff(w(t),t,t)+9*w(t)=Dira c(t-Pi), w(0)=1, D(w)(0)=0\}, w(t), laplace);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 21 "plot(rhs(\"),t=0..10);" }}}{EXCHG {PARA 0 "" 0 " " {TEXT -1 2 "5." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 94 "sys5:= \{diff(x(t),t)=-y(t)+Dirac(t), x(0)=0, diff(y(t),t)=x(t)+sin(t)*Heavis ide(t-Pi), y(0)=0\};" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 34 "dso lve(sys5,\{x(t),y(t)\}, laplace);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 24 "plot(rhs(\"[1]),t=0..13);" }}}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 0 "" }}}}{MARK "53 0 0" 0 }{VIEWOPTS 1 1 0 2 1 1805 }