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A proof that shows 2 = 1

Assume two numbers a, and b, where a = b

a^2=ab	Multiply both sides with a
a^2-b^2 = ab-b^2	Subtract b^2
(a+b)(a-b)=b(a-b)	Expand and take out b as a common factor
(a+b)=b	Cancel common factor on either side
2b=b	Tadaaaaaa
2=1