#1. POINT TO PROVE: IT IS IMPOSSIBLE TO DERIVE ALL MATHEMATICAL TRUTH
FROM ANY SET OF SELF-EVIDENT AXIOMS.
#2. IF ALL MATHEMATICAL TRUTHS CAN BE DERIVED FROM A CHOSEN SET OF
AXIOMS, THEN, IN PRINCIPLE, AN ALGORITHM "A" CAN BE CREATED TO TEST
WHETHER OR NOT ANY GIVEN THEOREM DERIVES FROM THE CHOSEN AXIOMS, I.E.:
WHETHER OR NOT IT IS TRUE OR FALSE.
#3. AT PRESENT WE DO NOT HAVE SUCH AN ALGORITHM. IF A CAN BE SHOWN TO BE
IMPOSSIBLE, THEN #1 IS ESTABLISHED.
#4. LIST THE FACTUAL STATEMENTS WHICH CAN BE MADE ABOUT NUMBERS.
EXAMPLES OF SUCH STATEMENTS ARE "X IS EVEN," "X IS ODD," "X IS PRIME","X
IS LESS THAN 100," ETC.
#5. CREATE A TABLE OF SUCH STATEMENTS, BEGINNING WITH THE SIMPLEST AND
MOVING TO THE MORE COMPLEX. WE WILL CALL OUR STATEMENTS 1, 2, 3, 4...
NOW WE NOTE THAT OUR TABLE CAN REFER TO ITS OWN STATEMENTS. SUPPOSE
STATEMENT 0 MEANS: "X IS EVEN", STATEMENT 1 "X IS ODD" ETC... WE LET THE
VERTICAL AXIS REPRESENTS THE STATEMENT NUMBER. THE HORIZONTAL AXIS
REPRESENTS ALL NUMBERS FROM 0 TO INFINITY. WE THEN ASK OURSELVES FOR
EACH NUMBER IN THE HORIZONTAL AXIS, "IS THE VERTICAL STATEMENT TRUE OF
THIS NUMBER?" WE WRITE Y BELOW IT IF IT IS TRUE, AND N IF IT ISN'T:
0 1 2 3 ....
0 (EVEN) N N Y N...
1 (ODD) N N Y Y
2 (PRIME) N N Y Y...
3 (x<100 ) Y Y Y Y....
... ..................
#6. FOR ANY NATURAL NUMBER (HORIZONTAL LINE) WE NOW HAVE A METHOD OF
DECIDING IF THE VERTICAL STATEMENT IS TRUE. SINCE EVERY POSSIBLE
STATEMENT OF THE SYSTEM CAN APPARENTLY BE LISTED AND SINCE EVERY NATURAL
NUMBER CAN ALSO BE LISTED, IT APPEARS WE HAVE A COMPLETE SYSTEM OF
NATURAL NUMBERS AND AXIOMS. NOTICE THAT EACH STATEMENT ON THE VERTICAL
AXIS PRODUCES ITS OWN UNIQUE HORIZONTAL LINE OF Ys AND Ns.
#7. CREATE A NEW WELL-DEFINED SEQUENCE OF Ys AND Ns BY FOLLOWING A
DIAGONAL ON THE CHART WE HAVE JUST CREATED. DO THIS BY TURNING EACH
DIAGONAL ELEMENT INTO ITS OPPOSITE. THE N AT 0/0 ON THE TABLE BECOMES A
Y. THE Y AT 1/1 BECOMES AN N. THE Y AT 2/2 BECOMES AN N. THE Y AT 3/3
BECOMES AN N AND SO FORTH. WE GET YNNN... DOES ANY STATEMENT WHICH HAS
ALREADY BEEN GIVEN PRODUCE THIS NEW SEQUENCE?
#8. STATEMENT 0 DOESN'T BECAUSE IT HAS AN N WHERE THE NEW STATEMENT HAS
Y. 1, 2, AND 3 DON'T BECAUSE THEY HAVE Ys WHERE THE NEW STATEMENT HAS
Ns. THIS WOULD HOLD TRUE TO INFINITY IF WE COULD MAKE OUR TABLE THAT
LONG,
#9. WE KNOW WE LEGITIMATELY CREATED THIS NEW Y & N PATTERN, IE: IT IS
TRUE. YET NONE OF THE EXISTING AXIOM STATEMENTS PRODUCE THIS DIAGONAL
STATEMENT. A NEW AXIOM IS NEEDED TO EXPRESS THE DIAGONAL.
10. IF WE WRITE A NEW STATEMENT (CALL IT R) THAT INCLUDES A PROCEDURE
FOR MAKING THIS DIAGONAL , AT SPACE R/R A NEW DIAGONAL LETTER WILL
APPEAR AND WE WILL HAVE TO ADD STATEMENT S TO REPRESENT THIS NEW
SEQUENCE. BUT AT S/S A NEW DIAGONAL NUMBER WILL APPEAR, REQUIRING A
STATEMENT T AND SO ON, INFINITELY.
11. THEREFORE ALGORITHM A IS IMPOSSIBLE, WHICH IS THE PROOF REQUIRED BY
#2. IT IS IMPOSSIBLE TO AUTOMATICALLY DERIVE ALL POSSIBLE MATHEMATICAL
TRUTH.