Practice Exercise 5 Solution:

Step 1: Define your variables.

x = the length of underwater pipe at $50,000 per mile

y = the length of land-based pipe at $30,000 per mile

C(y) = cost of the project

C(y) = $50,000 + $30,000(20 - y)

Step 2: The Domain of the function: Since y is the distance along the coastline, y can be found on the closed interval [0, 20].

Step 3: Graph the total cost equation on the interval [0, 20],

C(y) = $50,000 + $30,000(20 - y), C(9) = $1,080,000

Step 4: First Derivative test: Set C’(y) equal to zero.

C’(y) =

0 =

y = -9 and 9

The domain is [0, 20], therefore 9 is the absolute minimum.

Step 5: Test C(0), C(9), and C(20).

y distance

Total Cost C(y)

0

$1,200,000

9

$1,080,000

20

$1,166,190

 

Conclusion: The minimum cost occurs when x = 15 miles and y = 9 miles. The minimal cost is $1,080,000.