What does a finite Poynting flux at infinity imply in case of a uniformly accelerating charge? Ashok K. Singal ashokkumar.singal@gmail.com Dear all, This is my contribution on `radiation' from a uniformly accelerated charge. I am attaching a ppt file (converted into pdf to reduce size). It mostly comprises diagrams, along with some text. I am sorry for its length, but could not reduce it, without making it even worse. So I beg you to bear with me. EDITOR'S NOTE: The slides are at https://www.math.tamu.edu/~fulling/ar/singal1.pdf The summary of my arguments is: the Poynting flux at large distances from the charge is certainly there, but it is not 'radiation emitted away' by the uniformly accelerated charge. In a typical radiation scenario, the radiation goes away (to infinity!), with the charge remaining behind, perhaps not very far from its original location. However, in the case of a uniform acceleration, such is not true, the charge, moving with v~c, is not very far behind the wave-front r=ct. As the fields move toward infinity, so does the charge, and the fields, in fact, are all around the charge. As I show, contrary to some earlier claims, radiated power does not go beyond the horizon, into regions of space-time inaccessible to an observer co-accelerating with charge. The fields actually are the self-fields of the charge and as the charge picks up speed, the fields increase in strength, due to the acceleration fields, which build up the self-fields just sufficiently to values expected from the `present' velocity of uniformly accelerated charge. Naturally there is no radiation reaction on the uniformly accelerated charge, since no field energy is being `radiated away' from such a charge. This, of course, also makes it fully conversant with the strong principle of equivalence. The PPT file contains excerpts from one of my papers near completion, there might be minor typos or other mistakes, but I hope the meaning will be clear. At a first look some of my arguments might sound as far-fetched, but these all result from actual calculations, mostly given in ref. 3 (listed in the last slide). Any comments, criticism and suggestions will be most welcome. Ashok