COALITION MATH 151, FALL 1997 Group II (S. A. Fulling, assisted by Cary Lasher) Day 6.2 1. Projections (decomposition of vectors into components) (THIS SHOULD HAVE BEEN DONE ON THE PREVIOUS DAY.) A. Worked example with diagram and arithmetic; add a second vector to get components with respect to an orthonormal basis. B. Team RAT: Similar problem at end of vectors Web page (3 min to e-mail answer; all team members should understand) STUDENTS APPEARED VERY UNCOMFORTABLE WITH THIS, SO I CAME BACK TO IT ON THE FOLLOWING DAY WITH A LECTURE ON ROTATED COORDINATE SYSTEMS. 2. Parametric equations A. No big theorems or formulas in this subject; you need experience and a bit of basic terminology (e.g., tangent vector). B. Activity: (team transparencies) i. Write a parametric representation of the circle with center (2,1) and radius 4. (Let the parameter t vary from 0 to 2*Pi and have the "motion" start at the rightmost point on the circle.) ii. Find the tangent vector to this parametrized circle as a function of t, and at the point (2,5). (Sketch.) RAN OUT OF TIME AT THIS POINT; iii DONE NEXT DAY. iii. Suppose the parametrization is a real physical motion (so tangent vector = velocity vector). Find the acceleration vector as a function of t, and at the 4 extreme points of the circle. Sketch, and describe qualitatively. ALTHOUGH SOME STUDENTS KNEW THAT THE ACCELERATION POINTS TO THE CENTER, IT WAS NOT POSSIBLE TO FIND A TEAM THAT WOULD SO ARGUE, CONVINCINGLY AND IN GENERAL. POSTPONED THIS UNTIL THE DAY ON THE CHAIN RULE: C. Now suppose the motion is at a different speed, so the formulas involve sin(3t), etc. How can we calculate the velocity and acceleration? Look forward to next week's topics: i. Math: Chain rule (assert for the example) ii. Engineering: Units and dimensions. Let u be elapsed time in "Texas seconds" that are only 1/3 as long as normal New York seconds. Thus u = 3t, and in terms of u we have the problem previously solved. Then, converting from feet per Texas second to feet per second is just like converting highway costs from dollars per foot to dollars per yard: multiply by 3. For acceleration, we must do this again. 3. Comment on test results and midterm grades